William S asked:
If the reduction half-reaction Cd(2+)(aq) + e- ? Cd(s) has to be multiplied by 2 to balance the electrons before you add it to an oxidation half reaction, what is the electrical potential of this reduction half reaction?
I got an answer of -0.40 V. Am i correct?
JL asked:
What is the value of DGo in kJ at 25 oC for the reaction between the pair:
Cu(s) and Cr3 (aq) to give Cr(s) and Cu2 (aq)
Use the reduction potentials for Cr3 (aq) is -0.74 V and for Cu2 (aq) is 0.34 V.
I know that Cu is being reduced since its reduction potential is higher but then that makes Cr 0.74 for the oxidation potential. So E is positive and doesn’t that make G negative since G = -nFE?
I keep getting -6E2. How would it be positive?
nandayo asked:
When you’re working out what will be oxidised and reduced in a redox reaction for electrochemistry – why is it that the substance higher up on the standard reduction potentials list will always be the substance that is oxidised. I would’ve thought that..cause it was a more active metal (like Lithium) it would have been more easily reduced…not oxidised.
Help please!
but doesn’t lithium have a charge of 1+, meaning that one electron would bring it into its lowest energy state…isn’t this what it wants? Why would it get rid of an electron (i.e easily oxidise) if it can reduce to form a lithium atom.