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	<title>Comments on: Reduction Potential Question. Calculating delta G</title>
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	<link>http://alkaline-water.info/143/reduction-potential-question-calculating-delta-g/</link>
	<description>Learn How To Separate Fact From Fiction</description>
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		<title>By: Chem Man</title>
		<link>http://alkaline-water.info/143/reduction-potential-question-calculating-delta-g/comment-page-1/#comment-183</link>
		<dc:creator>Chem Man</dc:creator>
		<pubDate>Sat, 15 May 2010 09:39:13 +0000</pubDate>
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		<description>Cu -----&gt;  Cu2+ + 2e-  Eo = -0.34 V
Cr3+ + 3e-  ----&gt; Cr   Eo = -.073 V
3Cu +  2Cr3+  ----&gt;  3Cu2+ + 2Cr   Eocell = -1.07 V
This reaction will not occur spontaneously because the Eocell value is negative.

dGo = -nFEocell = -6 mol x 96,500 C/mol x (-1.07 J/C) = 620,000 J = 620 kJ

dGo is positive, meaning that no useful work can be obtained from this cell. The reason is that it is a nonspontaneous reaction.</description>
		<content:encoded><![CDATA[<p>Cu &#8212;&#8211;>  Cu2+ + 2e-  Eo = -0.34 V<br />
Cr3+ + 3e-  &#8212;-> Cr   Eo = -.073 V<br />
3Cu +  2Cr3+  &#8212;->  3Cu2+ + 2Cr   Eocell = -1.07 V<br />
This reaction will not occur spontaneously because the Eocell value is negative.</p>
<p>dGo = -nFEocell = -6 mol x 96,500 C/mol x (-1.07 J/C) = 620,000 J = 620 kJ</p>
<p>dGo is positive, meaning that no useful work can be obtained from this cell. The reason is that it is a nonspontaneous reaction.</p>
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